How do I know this and why? Please start with the facts. The player has already made a one-unit bet. He now has to decide whether he is better off making one more unit bet and playing the hand out or just losing the first unit.
If he Folds, the average loss per hand is one unit. So, it is logical that he should play a hand that results in less than one unit average loss. Because of the qualification conditions, the formula ultimately looks like this: Chances of winning with dealer qualification x 4 + prob. win with a dealer who does not meet the conditions x 3+ prob. of the tie x 2.
To end this similarity for each specific player, we need to know the chances of winning visit kingpoker99 (with dealer qualification and not qualification) and to tie. With a deck of cards there are 22,100 three-card hands that are likely to be dealt with first. After the three cards are dealt there are 18,424 chances of adding three cards. So, for each of the 22,100 unique player hands, there are 18,424 dealer’s hands.
So, for a specific three-card player card, I can have a computer program to deal with the dealer’s 18,424 remaining hands and determine how many lead to wins (with and without qualifying), losses and ties. I currently have a possibility. Now I can find where my fix is through trial and error.
Chances are I started by running the lowest possible Pair Hand (2-2-3) and getting this is definitely a game. Next I tried the lowest possible Ace High hand (A-2-4) and found it fair to play, so I kept going.